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9=-48u-64u^2
We move all terms to the left:
9-(-48u-64u^2)=0
We get rid of parentheses
64u^2+48u+9=0
a = 64; b = 48; c = +9;
Δ = b2-4ac
Δ = 482-4·64·9
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$u=\frac{-b}{2a}=\frac{-48}{128}=-3/8$
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